Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 111

Answer

$x=\dfrac{b+c}{a}$

Work Step by Step

Add $b$ to both sides. $ax-b+b=c+b$ Simplify. $ax=b+c$ Divide both sides by $a$. $\dfrac{ax}{a}=\dfrac{b+c}{a}$ Simplify. $x=\dfrac{b+c}{a}$
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