Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 114

Answer

$x=\dfrac{a+b}{c}$

Work Step by Step

Multiply both sides by $x$. $x\left ( \dfrac{a}{x} + \dfrac{b}{x}\right )=x\cdot c$ Use distributive property. $x\left ( \dfrac{a}{x} \right )+ x\left ( \dfrac{b}{x}\right )=xc$ Cancel common factors. $a+ b=xc$ Divide both sides by $c$. $\dfrac{a+b}{c}=\dfrac{xc}{c}$ Simplify. $\dfrac{a+b}{c}=x$
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