Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 105

Answer

No real solution.

Work Step by Step

The equation is in standard form $ax^2+bx+c=0$. We have $a=1,b=-5$ and $c=7$. The discriminant is $b^2-4ac$ $=(-5)^2-4(1)(7)$ $=25-28$ $=-3$ Since $-3<0$. There are no real solutions. Hence, the equation has no real solution.
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