Answer
Two unequal real solutions.
Work Step by Step
The equation is in standard form $ax^2+bx+c=0$.
We have $a=3,b=5$ and $c=-8$.
The discriminant is
$b^2-4ac$
$=(5)^2-4(3)(-8)$
$=25+96$
$=121$
Since $121>0$. There are two unequal real solutions.
Hence, the equation has two unequal real solutions.
