Answer
Repeated real solution.
Work Step by Step
The equation is in standard form $ax^2+bx+c=0$.
We have $a=25,b=-20$ and $c=4$.
The discriminant is
$=b^2-4ac$
$=(-20)^2-4(25)(4)$
$=400-400$
$=0$
Since $0=0$. There are two equal real solutions.
Hence, the equation has repeated real solution.
