Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 113

Answer

$x=\dfrac{abc}{a+b}$

Work Step by Step

Multiply both sides by $ab$. $ab\left ( \dfrac{x}{a} + \dfrac{x}{b}\right )=ab\cdot c$ Use distributive property. $ab\left ( \dfrac{x}{a} \right )+ ab\left ( \dfrac{x}{b}\right )=ab c$ Cancel common factors. $bx+ ax=ab c$ Factor out $x$. $x(b+ a)=ab c$ Divide both sides by $b+a$. $\dfrac{x(b+a)}{b+a}=\dfrac{abc}{b+a}$ Simplify. $x=\dfrac{abc}{a+b}$
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