Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 112

Answer

$ x=\dfrac{1-b}{a}$

Work Step by Step

Subtract $1$ from both sides. $1-ax-1=b-1$ Simplify. $-ax=b-1$ Divide both sides by $-a$. $\dfrac{-ax}{-a}=\dfrac{b-1}{-a}$ Simplify. $x=\dfrac{1-b}{a}$
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