Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A52: 116

Answer

$ x=\dfrac{ab}{c}$

Work Step by Step

Multiply both sides by $(x-a)(x+a)$. $(x-a)(x+a)\left (\dfrac{b+c}{x+a}\right )=(x-a)(x+a)\left ( \dfrac{b-c}{x-a} \right )$ Cancel common factors. $\Rightarrow (x-a)(b+c) =(x+a)(b-c)$ Use FOIL method on both sides. $bx+cx-ab-ac=bx-cx+ab-ac$ Add $ab+ac-bx+cx$ to both sides. $bx+cx-ab-ac+ab+ac-bx+cx=bx-cx+ab-ac+ab+ac-bx+cx$ Simplify by combining like terms. $2cx=2ab$ Divide both sides by $2c$. $\dfrac{2cx}{2c}=\dfrac{2ab}{2c}$ Simplify. $x=\dfrac{ab}{c}$
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