Answer
Two unequal real solutions.
Work Step by Step
The equation is in standard form $ax^2+bx+c=0$.
We have $a=2,b=-3$ and $c=-4$.
The discriminant is
$b^2-4ac$
$=(-3)^2-4(2)(-4)$
$=9+32$
$=41$
Since $41>0$. There are two unequal real solutions.
Hence, the equation has two unequal real solutions.
