Answer
$\{-3,-1\}$
Work Step by Step
Use the square root method by taking the square root of both sides.
$\sqrt{(x+2)^2}=\pm\sqrt {1}$
$x+2=\pm1$
Split the expression to obtain:
$x+2 =1\quad $ or $\quad x+2=-1$
Subtract $2$ from both sides of both equations.
$x+2-2 =1-2\quad$ or $\quad x+2-2=-1-2$
Simplify.
$x=-1\quad $ or $\quad x=-3$
Hence, the solution set is $\{-3,-1\}$.
