Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 37

Answer

$\{3\}$

Work Step by Step

Use distributive property. $z\cdot z^2+z\cdot 1=3+z^3$ Simplify. $z^3+z=3+z^3$ Subtract $z^3$ from both sides. $z^3+z-z^3=3+z^3-z^3$ Simplify. $z=3$ Hence, the solution to the equation is $\{3\}$.
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