Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 40

Answer

$\{0, 1\}$

Work Step by Step

Subtract $x^2$ from both sides. $x^3-x^2=x^2-x^2$ Simplify. $x^3-x^2=0$ Factor out $x^2$. $x^2(x-1)=0$ Use the Zero-Product Property. $x^2=0$ or $x-1=0$ Solve each equation for $x$. $x=0$ or $x=1$ Hence, the solution set to the equation is $\{0,1\}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.