Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 47

Answer

$\{6\}$.

Work Step by Step

Multiply both sides of the equation by $the LCD (x+5)(x-2)$ to eliminate all fractions. $(x+5)(x-2)\left (\dfrac{2}{x-2}\right )=(x+5)(x-2) \left (\dfrac{3}{x+5}+\dfrac{10}{(x+5)(x-2)}\right )$ Use the distributive property.on the right side of the equation, and cancel common factors on the left side to obtain: $2(x+5)=(x+5)(x-2) \left (\dfrac{3}{x+5}\right )+(x+5)(x-2) \left (\dfrac{10}{(x+5)(x-2)}\right )$ Simplify the right side of the equation by cancelling common factors: $2(x+5)=3(x-2)+10$ Use distributive property. $2x+10=3x-6+10$ Simplify by combining like terms on each side: $2x+10=3x+4$ Add $-2x-4$ to both sides. $2x+10-2x-4=3x+4-2x-4$ Simplify. $6=x$ Hence, the solution to the equation is $\{6\}$.
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