Answer
$\{-1,3\}$
Work Step by Step
Use the square root method by taking the square root of both sides.
$\sqrt{(x-1)^2}=\pm\sqrt {4}$
$x-1=\pm\sqrt {2^2}$
$x-1=\pm2$
Split the epxression to obtain:
$x-1 =2\quad $ or $\quad x-1=-2$
Add $1$ to both sides of both equation.
$x-1+1 =2+1\quad $ or $\quad x-1+1=-2+1$
Simplify.
$x=3\quad $ or $\quad x=-1$
Hence, the solution set of the given equation is $\{-1,3\}$.
