Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 34

Answer

$\{0.3\}$.

Work Step by Step

Multiply both sides by $2y$. $2y\left(\dfrac{4}{y}-5\right)=2y\left(\dfrac{5}{2y}\right)$ Use distributive property. $\begin{align*} 2y\left(\dfrac{4}{y}\right)-2y(5)&=2y\left(\dfrac{5}{2y}\right)\\ 2y\cdot\frac{4}{y}-2y\cdot 5&=2y\cdot \frac{5}{2y} \end{align*}$ Simplify. $\begin{align*} \require{cancel} 2\cancel{y}\cdot\frac{4}{\cancel{y}}-2y\cdot 5&=\cancel{2y}\cdot \frac{5}{\cancel{2y}}\\ 8-10y&=5 \end{align*}$ Add $10y-5$ to both sides. $8-10y+10y-5=5+10y-5$ Simplify. $3=10y$ Divide both sides by $10$. $\dfrac{3}{10}=\dfrac{10y}{10}$ Simplify. $0.3=y$ Hence, the solution to the equation is $\{0.3\}$.
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