Answer
$\{-2,2\}$
Work Step by Step
Apply absolute rule if $|u|=0$ then $u=0$ to obtain:
$x^2-4 =0$
$x^2-2^2 =0$
Use special rule $a^2-b^2=(a+b)(a-b)$ to obtain:
$(x+2)(x-2) =0$
Use Zero-Product Property which states that if $ab=0$, then $a=0$ or $b=0$ or both $a$ and $b$ are zero to obtain:
$x+2=0\quad $ or $\quad x-2 =0$
Solve each equation for $x$.
$x=-2\quad $ or $\quad x=2$
Hence, the solution set of the given equation is $\{-2,2\}$.
