Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 82

Answer

The solution set is $\{-6,6\}$.

Work Step by Step

Use the square root method by taking the square root of both sides. $\sqrt{x^2}=\pm\sqrt {36}$ $\sqrt{x^2}=\pm\sqrt {6^2}$ $x=\pm 6$ Hence, the solution set is $\{-6,6\}$.
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