Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 33

Answer

$\{2\}$.

Work Step by Step

Add numerators on the left hand side because denominators are same. $\dfrac{2+4}{y}=3$ Simplify. $\dfrac{6}{y}=3$ Multiply both sides by $\frac{y}{3}$. $\dfrac{y}{3}\cdot \dfrac{6}{y}=\dfrac{y}{3}\cdot 3$ Simplify. $2=y$ Hence, the solution to the equation is $\{2\}$.
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