Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.6 Solving Equations - A.6 Assess Your Understanding - Page A51: 36

Answer

$\{3\}$

Work Step by Step

Use FOIL method on the left side and special formula $(a-b)^2=a^2-2ab+b^2$ on the right side, then combine like terms on each side to obtain:. $\begin{align*} x\cdot x- x\cdot 3+2\cdot x-2\cdot 3&=x^2-6x+9\\ x^2- 3x+2 x-6&=x^2-6x+9\\ x^2-x-6&=x^2-6x+9 \end{align*}$ Add $-x^2+6x+6$ to both sides. $x^2-x-6-x^2+6x+6=x^2-6x+9-x^2+6x+6$ Simplify. $5x=15$ Divide both sides by $5$. $\dfrac{5x}{5}=\dfrac{15}{5}$ Simplify. $x=3$ Hence, the solution to the equation is $\{3\}$.
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