University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 223: 9


Mean Value Theorem does not satisfy.

Work Step by Step

Here, $f(x)=x^{\frac{2}[3}$and $f'(x)=\dfrac{2}{3x^{1/3}}$ . This means that the function is undefined at $x=0$; thus, it is not differentiable at $x=0$. Thus, the Mean Value Theorem does not satisfy.
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