University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 223: 30

Answer

Yes. See proof below.

Work Step by Step

Let $f(x)=2x+5$. Then, $f(0)=5$ and $f'(x)=2.$ Say that another function, $g(x)$ is such that $g(0)=2$ and $g'(x)=2$ for all x. Then, by Corollary 2, since $f'(x)=g'(x)$ for every x, it follows that $g(x)=f(x)+C$ where $C$ is some constant. We have: $\left\{\begin{array}{ll} g(0)=2, & f(0)=2\\ g(0)=f(0)+C & \end{array}\right.\ \quad $ from which we find C: $2=2+C$ $0=C$ So, $\quad g(x)=f(x).$ The answer is: yes.
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