## University Calculus: Early Transcendentals (3rd Edition)

$s(t)=4.9t^2+5t+10$
Here, $s=\dfrac{ds}{dt}=9.8t+5$, thus the general form of the function is: $s(t)=4.9t^2+5t+C$ Since we have $s(0)=10$ Therefore, $s(0)=10 \implies 10=4.9(0)^2+5(0)+C$ Thus, $C=10$ Hence, $s(t)=4.9t^2+5t+10$