University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 223: 29

Answer

True, $f(x)=f(-1)=3$ for all $x$.

Work Step by Step

By Corollary 1, we know that if $f'(x)=0$ on an open interval, then $f(x)=C$, where C is a constant. Since we know that $f'(x)=0$, we must have $f(x)=C$ and $C=3$ because $f(-1)=3$. Thus $f(x)=3$ for all $x$. True.
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