Answer
Yes
Work Step by Step
Here, $f(x)=\sqrt{x (1-x)}$ and $f'(x)=\dfrac{1}{2}(x(1-x))^{-1/2}((1-x)-x)$ .
This means that the function $f(x)$ is continuous on $[0,1]$ and differentiable on $(0,1)$. Thus, the Mean value Theorem is satisfied.
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 223: 11
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
