Answer
a) 4, b) 3, c) 3
Work Step by Step
We have $f(x)= x^2+c$ and $f'(x)=2x$
a) $f(0)=0 \implies 0=0^2+c \implies c=0$ and $f(2)= 2^2+0=4$
b) $f(1)=0 \implies 0=1^2+c \implies c=-1$ and $f(2)= 2^2-1=3$
c) $f(-2)=3 \implies 3=(-2)^2+c \implies c=-1$ and $f(2)= (2)^2-1=3$
Hence, a) 4, b) 3, c) 3