Answer
a) $y=x^2+C$
b) $y=x^2-x+C$
c) $y=x^3+x^2-x+C$
Work Step by Step
a) When $2x=(x^2)'$
Thus, $y'=2x \implies y=x^2+C$
b) When $2x-1=(x^2-x)'$
Thus, $y'=2x-1 \implies y=x^2-x+C$
c) When $3x^2+2x-1=(x^3+x^2-x)'$
Thus, $y'=x^2+x-x \implies y=x^3+x^2-x+C$