Chapter 4 - Section 4.2 - The Mean Value Theorem - Exercises - Page 223: 39

$f(x)=x^2-x$

Here, the derivative is given as: $f'(x)=2x+1$, thus, the general form of the function is: $f(x)=x^2-x+C$ Since the graph of the given function passes through $(0,0)$, $f(0)=0 \implies 0^2-0+C$ or, $C=0$ Hence, $f(x)=x^2-x$