Chapter 5 - Graphs and the Derivative - 5.2 Relative Extrema - 5.2 Exercises - Page 272: 14

f is decreasing in $(-\infty, -4)$ and f is increasing in $(-4,+\infty)$. The function has a relative minimum of -11 at x=-4

$f(x)=x^{2}+8x+5$ $f'(x)=2x+8$ $f'(x)=0 \rightarrow x=-4$ a>0 so we have: f is decreasing in $(-\infty, -4)$ and f is increasing in $(-4,+\infty)$ The function has a relative minimum of -11 at x=-4