Answer
f is decreasing in $(-\infty, 5)$ and f is increasing in $(5,+\infty)$.
The function has a relative minimum of 8 at x=5
Work Step by Step
$f(x)=x^{2}-10x+33$
$f'(x)=2x-10$
$f'(x)=0 \rightarrow x=5$
a>0 so we have: f is decreasing in $(-\infty, 5)$ and f is increasing in $(5,+\infty)$
The function has a relative minimum of 8 at x=5