Answer
$e^{-1}=\displaystyle \frac{1}{e} $
Work Step by Step
From the definition of logarithms,
for $a>0$, $a\neq 1$, and $x > 0$,
$y=\log_{a}x$ means $a^{y}=x$.
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The logarithm with base e is written as ln.
$-1=\displaystyle \log_{e}(\frac{1}{e})\ \ $ means $\ \ e^{-1}=\displaystyle \frac{1}{e} $.
