Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 41


$\boxed{x=\displaystyle \frac{1}{6}}$

Work Step by Step

$-2=\log_{x}(36)\ \ $ means $\ \ x^{-2}=36$ . $x^{-2}=6^{2}$ $x^{2}=(\displaystyle \frac{1}{6})^{-2}$ $\boxed{x=\displaystyle \frac{1}{6}}$
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