Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises: 40

Answer

$-2.059$

Work Step by Step

... Change of base: $\displaystyle \log_{a}x=\frac{\ln x}{\ln a}$. $\displaystyle \log_{2.8}0.12=\frac{\ln 0.12}{\ln 2.8}=$ (calculator) $\approx$-2.05926918318 rounded, $-2.059$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.