Answer
$x=2$ and $x=1$
Work Step by Step
$\log_{3}(x^{2}+17) - \log_{3}(x+5)=1$
$\log_{3}\frac{x^{2}+17}{x+5}=1$
$x^{2} + 17=3^{1}(x+5)$
$x^{2} - 3x + 2=0$
$x=2$ and $x=1$
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