## Calculus with Applications (10th Edition)

$\log_{7}$49 = 2
The logarithm formula using variables is: $\log_{B}$A = C Using the same variables, the spots they would go in the exponential formula is: B$^{C}$ = A So to write $7^{2}$ = 49 in logarithm form, you first have to look at which number corresponds to which variable in the exponential formula. In this case: 7 corresponds to B 2 corresponds to C and 49 corresponds to A Knowing which number corresponds to which variable in the exponential formula, you can then plug those into the logarithm formula to get your answer which will be: $\log_{7}$49 = 2