Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 64

Answer

7.407

Work Step by Step

$1.5(1.05)^x=2(1.01)^x$ $\ln[1.5(1.05)^x]=\ln [2(1.01)^x]$ $\ln1.5 + x\ln1.05 = \ln 2 +x\ln1.01$ $x\ln1.05-x\ln1.01=\ln 2 - \ln 1.5$ $x(\ln1.05-\ln1.01)=\ln 2 - \ln 1.5$ $x(\ln\frac{1.05}{1.01})=\ln\frac{2}{1.5}$ $x \approx 7.407$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.