Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises: 39

Answer

$-0.281$

Work Step by Step

... Change of base: $\displaystyle \log_{a}x=\frac{\ln x}{\ln a}$. $\displaystyle \log_{12}210=\frac{\ln 0.95}{\ln 1.2}=$ (calculator) $\approx$-0.281334227776 rounded, $-0.281$
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