Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 56

Answer

$\approx 0.582 $

Work Step by Step

$\ln (x+1)-\ln x=1$ $ln \frac{x+1}{x}=1$ means $\frac{x+1}{x}=e$ $x+1=xe$ $x(1-e)=-1$ $x=\frac{-1}{1-e}\approx 0.582 $
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