Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 60

Answer

$y = \frac{\ln 15}{2}$

Work Step by Step

$e^{2y}=15$ $\ln e^{2y}=\ln 15 $ $2y \ln e = \ln 15$ $y = \frac{\ln 15}{2}$ (because $\ln e =1$)
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