Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 61

Answer

$x\approx2.150$

Work Step by Step

$3^{x+1}=5^{x}$ $\ln 3^{x+1} = \ln 5^{x}$ $(x+1) \ln 3 = x\ln 5$ $(\ln 3)x + \ln 3= x\ln 5 $ $\ln 3 = (\ln 5)x - (\ln 3)x $ $x = \frac{\ln 3}{\ln 5 - \ln3} $ $x\approx2.150$
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