Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises: 24

Answer

0

Work Step by Step

From the definition of logarithms, for $a>0$, $a\neq 1$, and $x > 0$, $y=\log_{a}x$ means $a^{y}=x$. --------- $(\log_{e}x=\ln x)$, ... the base is e. $y=\log_{e}(1)\ \ $ means $\ \ e^{y}=1 $. So, $y=0.$
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