Answer
0
Work Step by Step
From the definition of logarithms,
for $a>0$, $a\neq 1$, and $x > 0$,
$y=\log_{a}x$ means $a^{y}=x$.
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$(\log_{e}x=\ln x)$, ... the base is e.
$y=\log_{e}(1)\ \ $ means $\ \ e^{y}=1 $.
So, $y=0.$