Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 63

Answer

1.224

Work Step by Step

$5(0.10)^x=4(0.12)^x$ $\ln[5(0.10)^x]=\ln [4(0.12)^x]$ $\ln5 + x\ln0.10 = \ln 4 +x\ln0.12$ $x\ln 0.10-x\ln 0.12=\ln 5 - \ln 4$ $x(\ln0.10-\ln0.12)=\ln 5- \ln 4$ $x(\ln\frac{0.10}{0.12})=\ln\frac{5}{4}$ $x \approx 1.224$
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