Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.5 Logarithmic Functions - 2.5 Exercises - Page 98: 14


$\log$$_{9}$81 = 2

Work Step by Step

To put the problem ($\log$$_{9}$81) into words it is simply asking: 9 to the what power equals 81? To make this simpler to read, you can rewrite this into exponential form. To do this, you would write it as: $9^{x}$ = 81 Now that the problem is easier to read, you can use multiplication to figure out what x equals. 9$\times$9=81 Since it takes 9 multiplying itself two times to get to 81, x = 2. So to write it into logarithm form, you have to answer what the problem is asking: 9 to what power equals 81? 2 $\log$$_{9}$81 = 2
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