Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 7

Answer

Vertex is (4, -3) Focus is (3.5, -3) Directrix is x = 4.5

Work Step by Step

$(y-k)^{2} = 4p(x-h)$ $y^{2} + 6y + 2x + 1 = 0$ $y^{2} + 6y = -2x - 1$ $y^{2} + 6y + 9 = -2x - 1 + 9$ $(y+3)^{2} = -2x +8 $ $(y+3)^{2} = -2(x - 4) $ 4p = -2 p = -0.5 Vertex is (h,k), so it is (4, -3) Focus is (h+p, k) = (4 - 0.5, -3) = (3.5, -3) Directrix is x = h-p = (4 - (-0.5)) = 4.5
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