Answer
$\dfrac{x^{2}}{9}-\dfrac{y^{2}}{16}=1$
Work Step by Step
From the given points, $a=3$ and $c=5$
Thus, $c^2=a^2+b^2$ or, $5^2=3^2+b^2$
$b^2=25-9=16$
Hence, the equation of hyperbola is: $\dfrac{x^{2}}{9}-\dfrac{y^{2}}{16}=1$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 43
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