## Calculus 8th Edition

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{4}=1$ and Foci: $( 2\pm \sqrt 5,1 )$
Here, $c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$ Hence, $\frac{(x-2)^2}{9}+\frac{(y-1)^2}{4}=1$ and Foci: $( 2\pm \sqrt 5,1 )$