Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 10

Answer

The equation of parabola is $(x -2)^2 = 2(y +2)$ which has focus $(2,-\frac{3}{2})$ and directrix is: $x=-\frac{5}{2}$.

Work Step by Step

The equation of a upward parabola is: $(x -h)^2 = 4p(y - k)$. Also, the equation of downward parabola is : $(y -h)^2 = 4p(x - k)$. Vertex: $(h, k) or (k,h)$ Focus: $(h, k + p) or (k+p,h)$. As we are given that vertex: $(2,-2)$ so, $p=\frac{1}{2}$ Hence, the equation of parabola is $(x -2)^2 = 2(y +2)$ which has focus $(2,-\frac{3}{2})$ and directrix is: $x=-\frac{5}{2}$.
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