Answer
$$(x-2)^2=-16(y-3)$$
Work Step by Step
The equation of a parabola when the distance of the point $(x,y)$ from the line $y=7$ is $|y-7|$.
Thus, $|y-7|=\sqrt {(x-2)^2+(y+1)^{2}}$
$-16y+48=x^2-4x+4$
Hence, $$(x-2)^2=-16(y-3)$$
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