Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 34

Answer

$$(x-2)^2=-16(y-3)$$

Work Step by Step

The equation of a parabola when the distance of the point $(x,y)$ from the line $y=7$ is $|y-7|$. Thus, $|y-7|=\sqrt {(x-2)^2+(y+1)^{2}}$ $-16y+48=x^2-4x+4$ Hence, $$(x-2)^2=-16(y-3)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.