## Calculus 8th Edition

$$(y+1)^2=-\frac{1}{2}(x-3)$$
As we are given that the parabola is passing through a point $(-15,2)$ so, $x=-15$ and $y=2$ Therefore, the equation of a parabola is: $(2+1)^2=4p(-15-3)$ or, $p=-\frac{1}{8}$ Hence, $$(y+1)^2=-\frac{1}{2}(x-3)$$