Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 35



Work Step by Step

As we are given that the parabola is passing through a point $(-15,2)$ so, $x=-15$ and $y=2$ Therefore, the equation of a parabola is: $(2+1)^2=4p(-15-3)$ or, $p=-\frac{1}{8}$ Hence, $$(y+1)^2=-\frac{1}{2}(x-3)$$
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