Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 47


$\dfrac{x^{2}}{9}-\dfrac{y^{2}}{36}=1$; equation of hyperbola.

Work Step by Step

From the given points we have $a=3$ and Asymptotes : $y=\pm2x$ this implies that $\frac{b}{a}=2$ Put $a=3$ thus, $\frac{b}{3}=2$ or $b=6$ or, $a^2=9, b^2=36$ Hence,$\dfrac{x^{2}}{9}-\dfrac{y^{2}}{36}=1$; equation of hyperbola.
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