## Calculus 8th Edition

$\dfrac{x^{2}}{9}-\dfrac{y^{2}}{36}=1$; equation of hyperbola.
From the given points we have $a=3$ and Asymptotes : $y=\pm2x$ this implies that $\frac{b}{a}=2$ Put $a=3$ thus, $\frac{b}{3}=2$ or $b=6$ or, $a^2=9, b^2=36$ Hence,$\dfrac{x^{2}}{9}-\dfrac{y^{2}}{36}=1$; equation of hyperbola.