Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 11

Answer

Foci: $(0, \pm \sqrt 2)$ Vertices : $(0, \pm 2)$
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Work Step by Step

$\frac{x^2}{2}+\frac{y^2}{4}=1$ Rewrite as $\frac{x^2}{(\sqrt 2)^2}+\frac{y^2}{(2)^2}=1$ $c^2=a^2-b^2=(2)^2-(\sqrt 2)^2=2$ $c=\sqrt 2$ Foci: $(0, \pm \sqrt 2)$ Vertices : $(0, \pm 2)$
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